Waec Physics/Geography 2015 Answers For Free (ENTER HERE)
[[Click Here To Refresh/Reload Page]]
Geography Answers Below....
(5b)
– Tourist attractions; e.g are holiday resorts like Olumo rocks,Idanre hills and the swiss Alps
– Sources of rivers;e.g River Niger from the guinewa highlands
– Rocks from highlands are used for constructions; e.g rocks from shai hill were used to construct the tema harbour in Ghana
– Minerals;These are mined from the highlands e.g tin and columbite from jos.
3a. Explain the following terms
===================
- Rotation of the earth
Rotation of the earth describes the spinning of the earth around its axis, resulting in the 24 hour phenomenon of day and night over the earth.
(under No3)
* Revolution of the earth
Revolution on the other hand describes the movement of the earth around the sun over a period of one year, causing seasons to occur.
(under No3)
Equinon: An equinox is a period in the orbit of a planet in which the planet's orbit and position cause the Sun to pass directly over the equator.An equinox occurs twice a year,around 20 March and 22 September
7a)
Environmental hazards can be defined as
the natural or human induced event
which poses a serious danger or risk to
the lives and properties of people in their
environment
7b)
-Volcanic eruptions
-Soil erosion
-Earth quakes
(5a)
-Fold mountains
-Block mountains
-Volcanic mountains
(5c)
-Barriers to communication;they serve as barrier
to communication as they prevent rails road and
airport construction
-Mountains promote soil erosion: Areas close to mountains are easily eroded due to speed of the
running water
(6a)
Climate can be defined as the average condition of a place over a long period of time e.g 35years
(6b)
-Torrid zone;this zone is found within the
tropics,the zone is very hot and it has a high
temperature
-Temperate zone;this zone is found within the
torrid and frigid zone,it has mild or moderate temperature and it has seasonal contrast in temperature
-Frigid zone;this zone is found in the polar
regions,it is generally cold with low temperature
throughout the year and it has a lot of ice caps in the greater larger part of the year
(6c)
-It is very simple to understand
-it is objective
-it is quantitative because numerical values are used for defining boundries of climatic groups
█████████████████████████
OBJ ANSWERS BELOW.......
PHYSIC OBJ
1-10 AACCCAABDC
11-20 BABAADAADD
21-30 DAAABBACDC
31-40 CDBDBACCAA
41-50 CCBADCCABD
░░░░░░░░░░░░░░░░░░░░░░░░░░░
Physics Essay Answers Below
░░░░░░░░░░░░░░░░░░░░░░░░░░░
(10di)
1/u 1/v=1/f
1/90 1/v=-1/18
1/v=-1/18-1/90
1/v=(-5-1)/90
1/v=-6/90
v=-90/6
=-15cm
(10ai)
Resonance ia a phenomenon whereby a vibrating body sets another bodies vibrating all oscillating at the same neutal frequency
(10aii)
(1)Radio-recieving circuit
(2)Sets of bob of pendulum
(10aiii)
Loudness is the sensation of sound reaching the ear while intensity is the ratio of the power to the area
(10b)
Wavelenght and speed
(8ai)
Uniform acceleration occurs when there is an equal changein n velocity with equal time interval no matter how small the time interval may be
(8aii)
V=wr
V=linear velocity
w=angular velocity
r=radius
(8b)
R= resultant
R=root(F1^2 F2^2)
R=root(30^2 40^2)
R=root(2500)
R=50N
(8c)
This is done to increase the surface friction in water
(8di)
Given;mass(m)=20kg
angle of inclineation(tita)=30degrees
F=UR
F=Umgcos*tita
ma*sin*tita=Umg cos tita
U=tan*tita
U=tan30
U=0.51
(8dii)
Frictional force(Fr)
Fr=Umgcos*tita
Fr=0.51*20*10*c0s30
Fr=90.9N
(1a)
Projectile is a body undergoing a motion under the combined effect of horizontal and vertical forces
(1b)
The horizontal components of the velocity remains the same because the body undergoes a uniform motion
2) Angle of projection(tita)=30degrees velocity(u)=150m/s At greatest height, v=0 t=Usin*tita/g t=(150*sin30degrees)/10 =150*0.5/10 t=7.5s
3) Given original lenght(Lo)=2.00m radius(r)=1.0mm=1*10^-3m Extension(e)=25mm=2*10^-3m Force(f)=10^3N stress =force/area Area(a)pie*R^2 =22/7*(10^-3)^2 3.142*10^16m^2 Stress=10^3/3.142*10^-6 =3.18*10^-1*10^3*10^6 =3.18*10^8Nm^-2Strain=Extension/original length =25*10^-3/2 =1.25*10^-2 Young modulus(Y)=3.18*10^8/1.25*10^-2 Y-2.54*10^10Nm^-2
4)
-By wind
-By increasing the cup surface area
-By reducing the temperature
7a) De brogile equation states that landa=h/mv where landa=wavelenght of light mv=p=momentum h=planck’s constant
7b) The equation is used to explain the wave-nature of matter
(12a)
Nucleon number is the sum of proton number and neutron number
(12b)
95=c a
95=c 2
c=95-2
c=93
(12bi)
Number of neutrons in americium-241 is
237-93=144
(12ii)
a=2, b=4, c=93
(12ci)
Gamma ray is not deflected because it has no charge
(12cii)
-It has the highest penetrating power
-it has low ionizing power
(12d)
N/Nt=(1/2)^t1/2/T
1/32=(1/2)^(110/t1/2)
5=110/t1/2
5t1/2=110
t1/2=110/5
t1/2=22s
t1/2=0.693/landa
22=0.693/landa
landa=0.693/22
landa=0.0315
landa=0.0315 per year
9bii.
(i) Biomass
(ii) water energy
(iii) wind energy and
(iv) solar enemy.
9c. Tomatoes kept in a moist jute bag stay
longer because the quantity od heat
required to change the state of solid to
liquid is very low as a result of the
moisture content of the jute bag.
9d. Given that V=0.28 M3 (i.e m square),
(tita)= 25’c (decgree c), Density (p)=
8.00×10 square kg|m sqaure
Specific latent heat of fudion of
iron=1.38×10 raise to power 5 j|kg,
SHC= 460 j|kg|k, tita= 1500’c (degree)
9di.
Total mass of the iron filling=density
x volume from Density=mass/volume, p=
8.00×10 raise to power 3kg|m raise to
power 3, v=0.28m raise to power 3
Therefore: m= 8.00 x10 raise to power 3
kg/ m raise to poer 3
M= 2240kg
: 70% of m= 70/100×2240/1
=1568kg
9dii. Q1= ml tita,Q2.=MC tita. Qr=Q1 Q2
But 10% of the iron filling
=10/100×2240/1=224kg
therefore Q1=2241.38×10 raise to power
5x(1500-25) 224x460x(1500)
=3091200×1475) (103040×1475)
4.5592×10 raise to power 10 151984000
=4.575×10 raise to power 10j
Answers Loading.... Solving Mode
Please Exercise A Bit Patient With Us. The Answer Are Still On Progress. Thnks!!
Before the answers will be posted here, you have to visit this page (link below) to study our symbols. So that you will understand the answers. The symbols are what we are going to be using to solve tomorrow's paper. Study them well!!
Read: SYMBOL CLASS FOR MATHS,PHYSICS, CHEMISTRY, ACCOUNT & OTHERS
The Answers Will Be Posted Here For Free. And Pls Give Us A Helping Hand By Inviting Your Friends To The Site. Thank You!
NOTE: DONT FORGET TO STAY ONLINE AND KEEP CLICKING REFRESH PAGE ON THIS PAGE SO THAT WHEN WE POST, YOU'LL SEE IT ON TIME.
Follow NEEDLOADED.TK on Twitter!
Join NEEDLOADED BBM Channel Now!!
Categories: Education
